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Physics (SSC, Railway, Police & All State exam)Chapter Unit

Electricity

Introduction to Electricity

  1. Definition:

    • Electricity is the flow of electric charge, typically carried by electrons in a conductor.
    • It manifests in the form of electric current, voltage (potential difference), and resistance.
  2. Basic Units:

    • Electric Charge (QQ): The fundamental property of matter that gives rise to electric force.
      • SI Unit: Coulomb (C).
    • Electric Current (II): The rate of flow of electric charge.
      • Formula: I=QtI = \frac{Q}{t}
      • SI Unit: Ampere (A), where 1A=1C/s1 \, A = 1 \, C/s.
    • Voltage (Potential Difference): The energy per unit charge required to move a charge between two points.
      • SI Unit: Volt (V), where 1V=1J/C1 \, V = 1 \, J/C.
    • Resistance (RR): The opposition to the flow of current.
      • SI Unit: Ohm (Ω\Omega), where 1Ω=1V/A1 \, \Omega = 1 \, V/A.

Ohm’s Law

  1. Statement:

    • The current through a conductor is directly proportional to the voltage across it and inversely proportional to the resistance.
    • Formula: V=IRV = IR
      • VV: Voltage.
      • II: Current.
      • RR: Resistance.
  2. Application:

    • Ohm’s law is applicable to conductors at constant temperature and materials that follow a linear relationship between voltage and current.

Resistivity and Conductivity

  1. Resistivity (ρ\rho):

    • The property of a material that determines its resistance.
    • Formula: R=ρLAR = \rho \frac{L}{A}
      • LL: Length of the conductor.
      • AA: Cross-sectional area of the conductor.
      • ρ\rho: Resistivity, which is a constant for a given material.
  2. Conductivity (σ\sigma):

    • The ability of a material to conduct electric current.
    • Formula: σ=1ρ\sigma = \frac{1}{\rho}

Series and Parallel Circuits

  1. Series Circuits:

    • Components are connected end-to-end.
    • Total Resistance: Rtotal=R1+R2++RnR_{\text{total}} = R_1 + R_2 + \dots + R_n
    • Current:
      • Same current flows through all components.
    • Voltage: Vtotal=V1+V2++VnV_{\text{total}} = V_1 + V_2 + \dots + V_n
  2. Parallel Circuits:

    • Components are connected across the same two points.
    • Total Resistance: 1Rtotal=1R1+1R2++1Rn\frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2} + \dots + \frac{1}{R_n}
    • Current: Itotal=I1+I2++InI_{\text{total}} = I_1 + I_2 + \dots + I_n
    • Voltage:
      • Same voltage across all components.

Electric Power

  1. Definition:

    • The rate at which electrical energy is consumed or converted into another form (heat, light, etc.).
    • Formula: P=VI=I2R=V2RP = VI = I^2 R = \frac{V^2}{R}
  2. SI Unit:

    • Watt (W), where 1W=1J/s1 \, W = 1 \, J/s.
  3. Energy Consumption:

    • Energy used is the power consumed over time: E=PtE = P \cdot t

Capacitors

  1. Definition:

    • A capacitor is a device used to store electric charge and energy in an electric field.
  2. Capacitance (CC):

    • The ability of a capacitor to store charge per unit voltage.
    • Formula: C=QVC = \frac{Q}{V}
    • SI Unit: Farad (F), where 1F=1C/V1 \, F = 1 \, C/V.
  3. Energy Stored in a Capacitor:

    • Formula: E=12CV2E = \frac{1}{2} C V^2
  4. Capacitors in Series and Parallel:

    • Series: 1Ctotal=1C1+1C2++1Cn\frac{1}{C_{\text{total}}} = \frac{1}{C_1} + \frac{1}{C_2} + \dots + \frac{1}{C_n}
    • Parallel: Ctotal=C1+C2++CnC_{\text{total}} = C_1 + C_2 + \dots + C_n

Numerical Example

  1. Example 1: A 10 Ω\Omega resistor is connected in series with a 20 Ω\Omega resistor. Find the total resistance.

    • Formula: Rtotal=R1+R2R_{\text{total}} = R_1 + R_2
    • Substituting values: Rtotal=10+20=30ΩR_{\text{total}} = 10 + 20 = 30 \, \Omega
  2. Example 2: A battery provides 12 V to a circuit with a resistance of 6 Ω\Omega. Calculate the current.

    • Using Ohm's Law: I=VR=126=2AI = \frac{V}{R} = \frac{12}{6} = 2 \, A
  3. Example 3: A capacitor of capacitance 5 μF\mu F is charged to 10 V. Find the energy stored in the capacitor.

    • Formula: E=12CV2E = \frac{1}{2} C V^2
    • Substituting values: E=125×106102=0.00025JE = \frac{1}{2} \cdot 5 \times 10^{-6} \cdot 10^2 = 0.00025 \, J

Electric Field and Electric Potential

  1. Electric Field (EE):

    • The region around a charged object where other charges experience a force.
    • Formula: E=FqE = \frac{F}{q}
      • FF: Force on a test charge qq.
    • For a point charge: E=kQr2E = \frac{kQ}{r^2}
      • kk: Coulomb’s constant (8.99×109Nm2/C28.99 \times 10^9 \, N \cdot m^2 / C^2).
      • QQ: Source charge.
      • rr: Distance from the charge.
  2. Electric Potential (VV):

    • The potential energy per unit charge at a point in an electric field.

    • Formula: V=UqV = \frac{U}{q}

      • UU: Potential energy, qq: Test charge.
    • For a point charge: V=kQrV = \frac{kQ}{r}

  3. Relation Between Electric Field and Potential:

    • Electric field is the negative gradient of electric potential: E=dVdrE = -\frac{dV}{dr}

Coulomb’s Law

  1. Statement:

    • Coulomb’s law describes the force between two point charges.
    • Formula: F=kQ1Q2r2F = k \frac{|Q_1 Q_2|}{r^2}
      • Q1Q_1 and Q2Q_2: Magnitudes of the charges.
      • rr: Distance between the charges.
  2. Nature of Force:

    • Attractive force if charges are of opposite sign.
    • Repulsive force if charges are of the same sign.

Gauss’s Law

  1. Statement:

    • The total electric flux through a closed surface is proportional to the charge enclosed within that surface.
    • Formula: ΦE=EdA=Qencϵ0\Phi_E = \oint E \cdot dA = \frac{Q_{\text{enc}}}{\epsilon_0}
      • ΦE\Phi_E: Electric flux.
      • EE: Electric field.
      • dAdA: Differential area.
      • QencQ_{\text{enc}}: Enclosed charge.
      • ϵ0\epsilon_0: Permittivity of free space (8.85×1012C2/Nm28.85 \times 10^{-12} \, C^2/N \cdot m^2).
  2. Applications:

    • Used to calculate electric fields of symmetrical charge distributions, such as spheres and cylinders.

Capacitance in Parallel Plate Capacitors

  1. Capacitance:

    • The ability of a capacitor to store charge.
    • Formula: C=ϵ0AdC = \frac{\epsilon_0 A}{d}
      • AA: Area of the plates.
      • dd: Distance between the plates.
  2. Dielectrics:

    • Materials that increase the capacitance of a capacitor by reducing the electric field between the plates.
    • Capacitance with a Dielectric: C=κϵ0AdC = \kappa \frac{\epsilon_0 A}{d}
      • κ\kappa: Dielectric constant of the material.

Current and Voltage

  1. Electric Current (II):

    • The rate of flow of charge through a conductor.
    • Formula: I=QtI = \frac{Q}{t}
  2. Ohm’s Law:

    • Relationship between current, voltage, and resistance.
    • Formula: V=IRV = IR
  3. Electrical Power:

    • The rate at which electrical energy is consumed or converted to other forms (heat, light, etc.).
    • Formula: P=I2R=V2RP = I^2 R = \frac{V^2}{R}

Kirchhoff’s Laws

  1. Kirchhoff’s Current Law (KCL):

    • The total current entering a junction equals the total current leaving the junction.
    • Formula: Iin=Iout\sum I_{\text{in}} = \sum I_{\text{out}}
  2. Kirchhoff’s Voltage Law (KVL):

    • The sum of the voltages around any closed loop in a circuit is zero.
    • Formula: V=0\sum V = 0

Numerical Examples

  1. Example 1: Two charges of +3μC+3 \, \mu C and 2μC-2 \, \mu C are separated by 0.5m0.5 \, m. Find the force between them.

    • Formula: F=kQ1Q2r2F = k \frac{|Q_1 Q_2|}{r^2}
    • Substituting values: F=8.99×1093×106×(2×106)(0.5)2F = 8.99 \times 10^9 \cdot \frac{|3 \times 10^{-6} \times (-2 \times 10^{-6})|}{(0.5)^2} F=8.99×1096×10120.25=2.16NF = 8.99 \times 10^9 \cdot \frac{6 \times 10^{-12}}{0.25} = 2.16 \, N
  2. Example 2: A parallel plate capacitor has a plate area of 1m21 \, m^2 and a plate separation of 1mm1 \, mm. Find its capacitance. (Use ϵ0=8.85×1012C2/Nm2\epsilon_0 = 8.85 \times 10^{-12} \, C^2/N \cdot m^2)

    • Formula: C=ϵ0AdC = \frac{\epsilon_0 A}{d}
    • Substituting values: C=8.85×101211×103=8.85×109F=8.85nFC = \frac{8.85 \times 10^{-12} \cdot 1}{1 \times 10^{-3}} = 8.85 \times 10^{-9} \, F = 8.85 \, nF

Magnetic Fields

  1. Magnetic Field (BB):

    • A region in space where a magnetic force is experienced by a moving charge.
    • SI Unit: Tesla (T), where 1T=1Ns/Cm1 \, T = 1 \, N \cdot s / C \cdot m.
    • Magnetic fields are produced by moving charges (currents) or magnetic materials.
  2. Magnetic Force on a Moving Charge:

    • Formula: F=qvBsinθF = qvB \sin \theta
      • qq: Charge.
      • vv: Velocity of the charge.
      • BB: Magnetic field strength.
      • θ\theta: Angle between velocity and magnetic field.
  3. Right-Hand Rule:

    • For the direction of magnetic force on a positive charge: Point the thumb in the direction of velocity, the fingers in the direction of the magnetic field, and the palm shows the direction of force.

Ampere’s Law

  1. Statement:

    • The magnetic field created by a current is proportional to the current and the path taken by the current.
    • Formula: Bdl=μ0Ienc\oint B \cdot dl = \mu_0 I_{\text{enc}}
      • μ0\mu_0: Permeability of free space (4π×107Tm/A4\pi \times 10^{-7} \, T \cdot m/A).
      • IencI_{\text{enc}}: Enclosed current.
  2. Magnetic Field Due to a Long Straight Current-Carrying Wire:

    • Formula: B=μ0I2πrB = \frac{\mu_0 I}{2 \pi r}
      • rr: Distance from the wire.

Faraday’s Law of Electromagnetic Induction

  1. Statement:

    • A change in magnetic flux through a circuit induces an electromotive force (EMF) in the circuit.
    • Formula: E=dΦBdt\mathcal{E} = -\frac{d\Phi_B}{dt}
      • E\mathcal{E}: Induced EMF.
      • ΦB\Phi_B: Magnetic flux.
  2. Lenz’s Law:

    • The direction of the induced current is such that it opposes the change in magnetic flux.

Self-Induction and Mutual Induction

  1. Self-Induction:

    • The phenomenon where a changing current in a coil induces an EMF in the same coil.
    • Formula: E=LdIdt\mathcal{E} = -L \frac{dI}{dt}
      • LL: Self-inductance.
  2. Mutual Induction:

    • When a changing current in one coil induces an EMF in a second coil.
    • Formula: E2=MdI1dt\mathcal{E}_2 = -M \frac{dI_1}{dt}
      • MM: Mutual inductance.

Electromagnetic Waves

  1. Definition:

    • Electromagnetic waves are transverse waves consisting of oscillating electric and magnetic fields, propagating through space.
    • They do not require a medium and can travel through a vacuum.
    • The speed of electromagnetic waves in a vacuum is the speed of light: c=1μ0ϵ0c = \frac{1}{\sqrt{\mu_0 \epsilon_0}}
  2. Properties:

    • They exhibit wave-particle duality and can be described by the same wave equations as light.
    • Electromagnetic waves include radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.
  3. Relation Between Electric and Magnetic Fields:

    • In an electromagnetic wave, the electric and magnetic fields are perpendicular to each other and to the direction of wave propagation.

Electric Circuits and Resistance

  1. Ohm’s Law for Circuits:

    • The relationship between current, voltage, and resistance in a circuit: V=IRV = IR
  2. Power in Electrical Circuits:

    • The rate at which electrical energy is used: P=IV=I2R=V2RP = IV = I^2 R = \frac{V^2}{R}
  3. Resistors in Series and Parallel:

    • Series: Rtotal=R1+R2++RnR_{\text{total}} = R_1 + R_2 + \dots + R_n
    • Parallel: 1Rtotal=1R1+1R2++1Rn\frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2} + \dots + \frac{1}{R_n}

Numerical Examples

  1. Example 1: A coil with a resistance of 10Ω10 \, \Omega carries a current of 2A2 \, A. Find the power dissipated in the coil.

    • Formula: P=I2RP = I^2 R
    • Substituting values: P=2210=40WP = 2^2 \cdot 10 = 40 \, W
  2. Example 2: A long straight wire carries a current of 5A5 \, A. Find the magnetic field at a distance of 0.2m0.2 \, m from the wire.

    • Formula: B=μ0I2πrB = \frac{\mu_0 I}{2 \pi r}
    • Substituting values: B=4π×10752π0.2=5×106TB = \frac{4\pi \times 10^{-7} \cdot 5}{2 \pi \cdot 0.2} = 5 \times 10^{-6} \, T
  3. Example 3: A capacitor of capacitance 10μF10 \, \mu F is charged to 12V12 \, V. Calculate the energy stored in the capacitor.

    • Formula: E=12CV2E = \frac{1}{2} C V^2
    • Substituting values: E=1210×106122=0.00072JE = \frac{1}{2} \cdot 10 \times 10^{-6} \cdot 12^2 = 0.00072 \, J

Recap: Key Points to Remember

  • Electricity involves the flow of electric charge, governed by Ohm’s law, Kirchhoff’s laws, and other principles.
  • Magnetic fields are created by currents, and changes in these fields induce electric currents through electromagnetic induction.
  • Power in electrical circuits is related to current, voltage, and resistance.
  • Electromagnetic waves are a combination of electric and magnetic fields, traveling through space at the speed of light.

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