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Chemistry (SSC, Railway, Police & All State exam)Chapter Unit

Atoms and Molecules

Introduction to Atoms

  • Atom: The smallest unit of matter that retains the properties of an element.
  • Historical Perspective:
    • The term "atom" comes from the Greek word atomos, meaning indivisible.
    • Proposed by ancient Greek philosophers Democritus and Leucippus.

Structure of an Atom

  1. Nucleus:

    • Small, dense central part of the atom.
    • Contains protons (positively charged) and neutrons (neutral particles).
    • Almost all the mass of an atom resides in the nucleus.
  2. Electrons:

    • Negatively charged particles revolving around the nucleus in specific orbits (energy levels).
    • Negligible mass compared to protons and neutrons.
  3. Subatomic Particles:

    ParticleChargeMass (in uu)Location
    Proton+1+11.0071.007Nucleus
    Neutron001.0091.009Nucleus
    Electron1-10.000550.00055Outside nucleus

Atomic Models

  1. Dalton’s Atomic Theory (1803):

    • Atoms are indivisible particles.
    • Atoms of a given element are identical in mass and properties.
    • Atoms combine in whole-number ratios to form compounds.
    • Limitations:
      • Failed to explain the discovery of subatomic particles.
      • Could not explain isotopes and isobars.
  2. Thomson’s Plum Pudding Model (1904):

    • Atom consists of a positively charged sphere with electrons embedded in it, like raisins in a pudding.
    • Limitations:
      • Could not explain atomic stability.
  3. Rutherford’s Nuclear Model (1911):

    • Based on the famous gold foil experiment:
      • Most alpha particles passed through the foil (indicating an atom is mostly empty space).
      • Few were deflected (indicating a dense, positively charged nucleus).
    • Key features:
      • Atom has a small, dense nucleus containing protons and neutrons.
      • Electrons revolve around the nucleus.
    • Limitations:
      • Could not explain the stability of atoms or energy levels.

Molecules

  • Definition: Molecules are groups of two or more atoms bonded together chemically.
  • Types of Molecules:
    1. Molecules of Elements:
      • Contain atoms of the same element.
      • Examples: H2\text{H}_2, O2\text{O}_2, N2\text{N}_2.
    2. Molecules of Compounds:
      • Contain atoms of different elements.
      • Examples: H2O\text{H}_2\text{O}, CO2\text{CO}_2, CH4\text{CH}_4.

Atomic Mass and Molecular Mass

  1. Atomic Mass:

    • The mass of a single atom, expressed in atomic mass units (uu).
    • 1 atomic mass unit (uu) = 112\frac{1}{12} the mass of a carbon-12 atom.
    • Example: Atomic mass of hydrogen = 1u1 \, u, oxygen = 16u16 \, u.
  2. Molecular Mass:

    • The sum of atomic masses of all atoms in a molecule.
    • Example:
      • Molecular mass of H2O\text{H}_2\text{O}: Mass=(2×1u)+(1×16u)=18u\text{Mass} = (2 \times 1 \, u) + (1 \times 16 \, u) = 18 \, u

Mole Concept

  • Definition: One mole is the amount of substance containing 6.022×10236.022 \times 10^{23} particles (atoms, molecules, or ions). This number is known as Avogadro’s Number (NAN_A).
  • Molar Mass: The mass of one mole of a substance, expressed in grams per mole (g/mol\text{g/mol}).
    • Example:
      • Molar mass of oxygen (O2\text{O}_2) = 32g/mol32 \, \text{g/mol}.

Law of Conservation of Mass

  • Statement: Mass is neither created nor destroyed in a chemical reaction.
  • Example:
    • Reaction: H2+O2H2O\text{H}_2 + \text{O}_2 \rightarrow \text{H}_2\text{O}.
    • Total mass of reactants = Total mass of products.

Laws of Chemical Combination

The behavior of atoms and molecules in chemical reactions is governed by these fundamental laws:

  1. Law of Definite Proportions (Proust’s Law):

    • Statement: A given compound always contains the same elements in the same proportion by mass, regardless of the source or preparation method.
    • Example:
      • Water (H2O\text{H}_2\text{O}) always contains hydrogen and oxygen in the ratio 2:162:16 by mass.
  2. Law of Multiple Proportions:

    • Statement: When two elements combine to form more than one compound, the masses of one element that combine with a fixed mass of the other are in a simple whole-number ratio.
    • Example:
      • Carbon and oxygen form two compounds:
        • CO\text{CO}: Carbon and oxygen combine in a 12:1612:16 ratio.
        • CO2\text{CO}_2: Carbon and oxygen combine in a 12:3212:32 ratio.
        • Ratio of oxygen masses: 16:32=1:216:32 = 1:2.
  3. Gay-Lussac’s Law of Gaseous Volumes:

    • Statement: When gases react together at constant temperature and pressure, their volumes are in simple whole-number ratios.
    • Example:
      • Reaction: 2H2+O22H2O2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}.
      • Volume ratio: 2:1:22:1:2.
  4. Avogadro’s Hypothesis:

    • Statement: Equal volumes of gases, at the same temperature and pressure, contain an equal number of molecules.
    • Application:
      • Forms the basis of the molar volume concept: 1mol1 \, \text{mol} of any gas occupies 22.4L22.4 \, \text{L} at STP.

Atomic Number and Mass Number

  1. Atomic Number (ZZ):

    • Number of protons in the nucleus of an atom.
    • Determines the chemical identity of an element.
    • Example: Hydrogen (Z=1Z = 1), Carbon (Z=6Z = 6).
  2. Mass Number (AA):

    • Sum of protons and neutrons in the nucleus. A=Z+Number of NeutronsA = Z + \text{Number of Neutrons}
    • Example: For oxygen (Z=8Z = 8, neutrons = 88), A=8+8=16A = 8 + 8 = 16.

Isotopes, Isobars, and Isotones

  1. Isotopes:

    • Atoms of the same element with the same atomic number (ZZ) but different mass numbers (AA).
    • Example:
      • Hydrogen isotopes: Protium (1H^1\text{H}), Deuterium (2H^2\text{H}), Tritium (3H^3\text{H}).
  2. Isobars:

    • Atoms of different elements with the same mass number (AA) but different atomic numbers (ZZ).
    • Example:
      • C614\text{C}^{14}_6 and N714\text{N}^{14}_7.
  3. Isotones:

    • Atoms of different elements with the same number of neutrons.
    • Example:
      • C614\text{C}^{14}_6 (neutrons = 8) and O816\text{O}^{16}_8 (neutrons = 8).

Molecule and Atomicity

  1. Molecule:

    • A group of atoms bonded together, representing the smallest unit of a chemical compound.
  2. Atomicity:

    • The number of atoms in a molecule.
    • Types:
      • Monoatomic: He,Ne\text{He}, \text{Ne}
      • Diatomic: O2,H2\text{O}_2, \text{H}_2
      • Triatomic: O3,CO2\text{O}_3, \text{CO}_2
      • Polyatomic: P4,S8\text{P}_4, \text{S}_8

Empirical and Molecular Formulas

  1. Empirical Formula:

    • Represents the simplest whole-number ratio of atoms in a compound.
    • Example:
      • Glucose: Empirical formula = CH2O\text{CH}_2\text{O}.
  2. Molecular Formula:

    • Represents the actual number of atoms of each element in a molecule.
    • Related to the empirical formula by: Molecular formula=n×Empirical formula\text{Molecular formula} = n \times \text{Empirical formula}
    • Example:
      • Glucose: Molecular formula = C6H12O6\text{C}_6\text{H}_{12}\text{O}_6.

Chemical Bonding in Molecules

Atoms combine to form molecules through chemical bonds. These bonds are of various types:

  1. Ionic Bond:

    • Formed by the transfer of electrons from one atom to another.
    • One atom becomes a positively charged ion (cation), and the other becomes a negatively charged ion (anion).
    • Example:
      • Sodium chloride (NaCl\text{NaCl}): Sodium donates one electron to chlorine. NaNa++e\text{Na} \rightarrow \text{Na}^+ + e^- Cl+eCl\text{Cl} + e^- \rightarrow \text{Cl}^-
  2. Covalent Bond:

    • Formed by the sharing of electrons between two atoms.
    • Example:
      • Water (H2O\text{H}_2\text{O}): Each hydrogen atom shares one electron with oxygen.
  3. Metallic Bond:

    • Formed by the attraction between a lattice of positive metal ions and a sea of delocalized electrons.
    • Example:
      • Metals like iron, copper.
  4. Hydrogen Bond:

    • A weak bond formed between a hydrogen atom covalently bonded to a highly electronegative atom (e.g., oxygen, nitrogen) and another electronegative atom.
    • Example:
      • Hydrogen bonding in water molecules.

Mole Concept and Calculations

  1. Relationship Between Mole, Mass, and Molar Mass: n=mMn = \frac{m}{M} Where:

    • nn = Number of moles,
    • mm = Mass of substance (in grams),
    • MM = Molar mass (in g/mol\text{g/mol}).
  2. Number of Particles in a Mole: N=n×NAN = n \times N_A Where:

    • NN = Total number of particles,
    • nn = Number of moles,
    • NAN_A = Avogadro’s number (6.022×10236.022 \times 10^{23}).
  3. Molar Volume of Gases:

    • At STP (0C0^\circ \text{C}, 1atm1 \, \text{atm}), 1 mole of any gas occupies 22.4L22.4 \, \text{L}.

Chemical Reactions and Balancing Equations

  1. Chemical Reaction:

    • A process in which one or more substances (reactants) are converted into one or more new substances (products).
    • Example: 2H2+O22H2O\text{2H}_2 + \text{O}_2 \rightarrow \text{2H}_2\text{O}
  2. Balancing Chemical Equations:

    • Ensure the number of atoms of each element is the same on both sides of the equation.
    • Example:
      • Unbalanced: H2+O2H2O\text{H}_2 + \text{O}_2 \rightarrow \text{H}_2\text{O}.
      • Balanced: 2H2+O22H2O\text{2H}_2 + \text{O}_2 \rightarrow \text{2H}_2\text{O}.

Stoichiometry

  1. Definition:

    • The calculation of quantities of reactants and products in a chemical reaction.
  2. Steps for Stoichiometric Calculations:

    • Write the balanced chemical equation.
    • Convert the given quantity (mass/volume) into moles.
    • Use the mole ratio from the balanced equation.
    • Convert the result back to the required unit.
  3. Example:

    • Reaction: 2H2+O22H2O\text{2H}_2 + \text{O}_2 \rightarrow \text{2H}_2\text{O}.
    • If 4mol4 \, \text{mol} of H2\text{H}_2 reacts, how many moles of H2O\text{H}_2\text{O} are produced? Mole ratio: H2:H2O=2:2\text{Mole ratio: } \text{H}_2 : \text{H}_2\text{O} = 2:2 Moles of H2O=4mol\text{Moles of } \text{H}_2\text{O} = 4 \, \text{mol}

Empirical and Molecular Formula Calculation

  1. Steps to Determine Empirical Formula:

    • Determine the mass or percentage composition of each element.
    • Convert masses to moles.
    • Divide by the smallest number of moles to get the simplest ratio.
  2. Steps to Determine Molecular Formula:

    • Calculate the empirical formula mass.
    • Determine the ratio: Molecular Formula=n×Empirical Formula\text{Molecular Formula} = n \times \text{Empirical Formula} Where: n=Molar MassEmpirical Formula Massn = \frac{\text{Molar Mass}}{\text{Empirical Formula Mass}}
  3. Example:

    • Compound: 40%C40\% \, \text{C}, 6.7%H6.7\% \, \text{H}, 53.3%O53.3\% \, \text{O}.
    • Molar mass: 180g/mol180 \, \text{g/mol}.
    • Empirical formula: CH2O\text{CH}_2\text{O}.
    • Empirical formula mass: 12+2(1)+16=30g/mol12 + 2(1) + 16 = 30 \, \text{g/mol}.
    • Molecular formula: n=18030=6n = \frac{180}{30} = 6 Molecular formula=C6H12O6\text{Molecular formula} = \text{C}_6\text{H}_{12}\text{O}_6

Summary Table of Key Concepts

ConceptKey Formula/ValueExample
Avogadro’s Number (NAN_A)6.022×10236.022 \times 10^{23} particles/molUsed in mole calculations
Molar Volume at STP22.4L22.4 \, \text{L}1 mole of O2\text{O}_2 occupies 22.4L22.4 \, \text{L}
Empirical FormulaSimplest whole-number ratio of atomsCH2O\text{CH}_2\text{O}
Molecular Formulan×Empirical Formulan \times \text{Empirical Formula}C6H12O6\text{C}_6\text{H}_{12}\text{O}_6

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